Hi,

I am playing with he surface graph. I'm trying to display an arch just now with this code:

int maxj = 10;
for (int i = 0; i <= 180; i++)
      {
       for (int j = 0; j < maxj; j++)
       {
          //x
          surface.XValues.Add(j);
          //y
          surface.Values.Add(Math.Round(Math.Sin(i * Math.PI / 180) * 100, 2));
          //z
          surface.ZValues.Add(Math.Round(Math.Cos(i * Math.PI / 180) * 100 + 100, 2));
          surface.Colors.Add(returnColor(0, 20, 10));
       }
      }

My problem is that if the maxj is 10 then I cannot see the graph, if I decrease it to 3 then it is displayed.

It is not the number of points as if display the same or even more points without drawing the arc, using Sin/Cos then it works.

Any idea?

Thanks,
Daniel

Thank you, I need to color each point the way I want to so I think I just going to stay with the triangulated surface.

I am just wondering can nevron display a torus? or at least the top half of it?

No worries.
It can display torus.