Hi,

I tested your solution and it works just like mine, it's, in fact, a bit more "clean" so I will use it.

So it looks like I found a microscopic bug.

Thanks a lot for your answers.

Hi Jeremy,

When the axis uses paging it will also automatically apply clip to the plot area - it looks that in this case the pixels covered by the step line are also clipped. To work around this you can consider to extend the y axis area using a view range inflate - check out the following example:

All Examples\Axes\General\View Range Inflate

You need to apply an absolute inflate to the axis - for example one or two point inflate should do the job...

Best Regards,
Nevron Support Team

While I was making an example, I found the problem.

In x axis I have a date time scale with a paging view with the following code:

' X axis
Dim dateTimeScale As NDateTimeScaleConfigurator = New NDateTimeScaleConfigurator
M_Chart.Axis(StandardAxis.PrimaryX).ScaleConfigurator = dateTimeScale

' configure the x axis to use date time paging
StartDate = DateAdd(DateInterval.Second, -10, Now())
DateTimePagingView = New NDateTimeAxisPagingView(StartDate, New NDateTimeSpan(120, NDateTimeUnit.Second))
DateTimePagingView.Enabled = True
M_Chart.Axis(StandardAxis.PrimaryX).PagingView = DateTimePagingView
M_Chart.Axis(StandardAxis.PrimaryX).ScrollBar.Visible = True

When I activate the paging view, the problem occur, when I disable it, it work fine.

In the attachment you will find a demo with a checkbox which disable the paging view.

I hope you will find the problem.

Hi Jeremy,

Please submit an application that replicates the problem for further review. We tested with the following code and were not able to replicate this problem:

   NChart chart = nChartControl1.Charts[0];

   chart.Axis(StandardAxis.PrimaryX).Visible = false;

   NStepLineSeries stepline = new NStepLineSeries();
   chart.Series.Add(stepline);

   stepline.Values.Add(10);
   stepline.Values.Add(20);
   stepline.Values.Add(30);
   stepline.Values.Add(10);
   stepline.BorderStyle.Color = Color.Orange;

   chart.Wall(ChartWallType.Back).VisibilityMode = WallVisibilityMode.Hidden;

   nChartControl1.BackgroundStyle.FillStyle = new NColorFillStyle(Color.Black);

Best Regards,
Nevron Support Team

I make more test with that problem.

I make one graph with 4 Y axis with anchor alongside axis. (I don't know if it's understandable, but see the attachment)

In the attachment we can see the values at 0 are half hidden by something. (With standard colouration it's the same problem)

The work around with the -0.01 value work there too.

So what is the "something" and how that can be corrected?


Thank you in advance.

Hi,

Thanks for your reply.

After a bit more test, I try without Xvalues and it works and if I reactivate XValues, it fail again.

Hi Jeremy,

Are you sure the x axis not visible? We tested with the following code and everything was working Ok (there is not overdraw from the chart back wall on the series):

   NChart chart = nChartControl1.Charts[0];

   NStepLineSeries stepLine = new NStepLineSeries();

   stepLine.BorderStyle.Color = Color.Red;
   stepLine.DataLabelStyle.Visible = false;

   for (int i = 0; i < 10; i++)
   {
    stepLine.Values.Add(i % 2);
   }

   chart.Series.Add(stepLine);

   chart.Axis(StandardAxis.PrimaryX).Visible = false;

Best Regards,
Nevron Support Team

Hi again,

(Yeah I know it's my second topic today)

I have another problem.

I try to do a StepLine graph with 2 Y value possible 0 or 1. Primary Y axis is displayed with a margin, primary X axis is not visible.

I work good except when the value is 0 the border of graph area hide the value. In the 1st picture, the border width is 1 and the line width is 2 so we can see a bit of the line but in picture 2 the line width is 1 so we can't see it.

I have a work around who consist in setting Y axis range with -0.01 to 1 but it's not a good solution and we can see a little bit of axis under the 0 tick what is not beautiful.

I can keep it like this but if a better solution exist, I take it.


Thanks to all the people who will help me.